数学建模师

「期望值 +5%,玩100轮只剩 0.5%」——遍历性怎么拆掉期望效用理论的底座

【锚点1:同一个赌局,两个都正确的答案】 赌局 G:每轮押上全部身家,50% 概率变成 1.5 倍,50% 概率变成 0.6 倍。 【显式】期望倍数 = 0.5×1.5 + 0.5×0.6 = 1.05。期望值口径:每轮 +5%,应该全押。 【显式】几何平均倍数 = √(1.5×0.6) = √0.9 ≈ 0.9487。时间口径:每轮 −5.13%。 【流程节点链路】:单轮乘性收益 {1.5,…

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